What is the sum from n=0 to infinity of (-1)^n(2)^n ?

The sum from n=0 to infinity of (-1)^n(2)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (-1)^n(2)^n

n = 0 \sum \infty (- 1)^{n} (2)^{n}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} \cdot 2^{n}

Apply Series Ratio Test:

diverges

= diverges

f (x) = x^{2} - 2, - 3, 1

x y^{^{'''}} + 2 y^{^{''}} = 6 x

\int \frac{x ^{4} + x ^{3} + 2 x + 1}{x ^{2} + x} d x

\frac{d}{d x} (\frac{x ^{2} + 5}{x ^{2} - 1})

\frac{d}{d x} (2 x^{2} + 4 x - 1)

What is the sum from n=0 to infinity of (-1)^n(2)^n ?
The sum from n=0 to infinity of (-1)^n(2)^n is diverges