What is area (12x-x^3+1),x^2+29,{0,7} ?

The answer to area (12x-x^3+1),x^2+29,{0,7} is 7399/12

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area (12x-x^3+1),x^2+29,{0,7}

area

(12 x - x^{3} + 1), x^{2} + 29, {0, 7}

\frac{7399}{12}

Solution steps

Apply the area formula:

\int_{0}^{7} 12 x - x^{3} + 1 - (x^{2} + 29) d x

Solve

\int_{0}^{7} 12 x - x^{3} + 1 - (x^{2} + 29) d x : \frac{7399}{12}

The area is:

= \frac{7399}{12}

x \to 0 + lim (4 + ln (x))

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 5 x - y}

(x^{2} + 8)

f (x) = \frac{x ^{2}}{x ^{2} + x - 2}

\int (x^{2} - 3) sin (2 x) d x

What is area (12x-x^3+1),x^2+29,{0,7} ?
The answer to area (12x-x^3+1),x^2+29,{0,7} is 7399/12