What is the slope ofintercept (3,-8),(-6,-3) ?

The slope ofintercept (3,-8),(-6,-3) is y=-5/9 x-19/3

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slope ofintercept (3,-8),(-6,-3)

slope intercept

(3, - 8), (- 6, - 3)

y = - \frac{5}{9} x - \frac{19}{3}

Solution steps

Compute the slope

(3, - 8), (- 6, - 3) : m = - \frac{5}{9}

Compute the

y

intercept:

b = - \frac{19}{3}

Construct the line equation

y = mx + b

where

m = - \frac{5}{9}

and

b = - \frac{19}{3}

y = - \frac{5}{9} x - \frac{19}{3}

\int \frac{3 x + 11}{x ^{2} - x - 6} d x

y = - 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}

\frac{d y}{d x} = (y^{2} - 1) x

\frac{d}{d x} ((x^{2} + 3 x - 1) e^{x})

What is the slope ofintercept (3,-8),(-6,-3) ?
The slope ofintercept (3,-8),(-6,-3) is y=-5/9 x-19/3