What is the tangent of x^2+xy+2y^2=4,(-2,1) ?

The tangent of x^2+xy+2y^2=4,(-2,1) is y= 3/2 x+4

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tangent of x^2+xy+2y^2=4,(-2,1)

tangent of

x^{2} + x y + 2 y^{2} = 4, (- 2, 1)

y = \frac{3}{2} x + 4

Solution steps

Find the slope of

x^{2} + x y + 2 y^{2} = 4 : \frac{d y}{d x} = \frac{- 2 x - y}{x + 4 y}

Compute the slope of

x^{2} + x y + 2 y^{2} = 4

(- 2, 1) : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(- 2, 1) : y = \frac{3}{2} x + 4

y = \frac{3}{2} x + 4

9 y^{^{''}} + 6 y^{^{'}} + y = 0, y (- 3) = - 2, y^{^{'}} (1) = - 1

\frac{d}{d x} (x^{2} - x y)

y^{^{'}} = 1 + x^{2} + y^{2} + x^{2} y^{2}

\int_{0}^{1} \frac{y}{e ^{2 y}} d y

\frac{\partial}{\partial y} (x y^{3} z^{2})

What is the tangent of x^2+xy+2y^2=4,(-2,1) ?
The tangent of x^2+xy+2y^2=4,(-2,1) is y= 3/2 x+4