What is the integral from 0 to 1 of 8^x ?

The integral from 0 to 1 of 8^x is 7/(3ln(2))

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integral from 0 to 1 of 8^x

\int_{0}^{1} 8^{x} d x

\frac{7}{3 ln ( 2 )}

Solution steps

\int_{0}^{1} 8^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{8 ^{x}}{ln ( 8 )}]_{0}^{1}

Simplify

ln (8) : 3 ln (2)

= [\frac{8 ^{x}}{3 ln ( 2 )}]_{0}^{1}

Compute the boundaries:

\frac{7}{3 ln ( 2 )}

= \frac{7}{3 ln ( 2 )}

\int \frac{1}{1 - 3 x ^{2}} d x

\frac{\partial}{\partial z} (5 e^{x} cos (yz))

- \frac{9}{x ^{2}}

0.8 x + 19, \frac{355.6}{x + 6}

x \to 0 lim ((1 - 7 x)^{\frac{4}{x}})

What is the integral from 0 to 1 of 8^x ?
The integral from 0 to 1 of 8^x is 7/(3ln(2))