What is the derivative of f(x)=3x^2e^x+e^x(x^3+8) ?

The derivative of f(x)=3x^2e^x+e^x(x^3+8) is e^xx^3+6e^xx^2+6e^xx+8e^x

What is the first derivative of f(x)=3x^2e^x+e^x(x^3+8) ?

The first derivative of f(x)=3x^2e^x+e^x(x^3+8) is e^xx^3+6e^xx^2+6e^xx+8e^x

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derivative of

f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 8)

e^{x} x^{3} + 6 e^{x} x^{2} + 6 e^{x} x + 8 e^{x}

Solution steps

\frac{d}{d x} (3 x^{2} e^{x} + e^{x} (x^{3} + 8))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2} e^{x}) + \frac{d}{d x} (e^{x} (x^{3} + 8))

\frac{d}{d x} (3 x^{2} e^{x}) = 3 (2 x e^{x} + e^{x} x^{2})

\frac{d}{d x} (e^{x} (x^{3} + 8)) = e^{x} (x^{3} + 8) + 3 x^{2} e^{x}

= 3 (2 x e^{x} + e^{x} x^{2}) + e^{x} (x^{3} + 8) + 3 x^{2} e^{x}

Simplify

3 (2 x e^{x} + e^{x} x^{2}) + e^{x} (x^{3} + 8) + 3 x^{2} e^{x} : e^{x} x^{3} + 6 e^{x} x^{2} + 6 e^{x} x + 8 e^{x}

= e^{x} x^{3} + 6 e^{x} x^{2} + 6 e^{x} x + 8 e^{x}

y ln (x) - x^{2} y = x y^{^{'}}

\frac{\partial}{\partial y} (x^{3 y})

x \to 0 lim (a^{\frac{1}{x}})

\int x e^{(x + 2)} d x

y^{^{''}} + 7 y^{^{'}} + 10 y = 0

What is the derivative of f(x)=3x^2e^x+e^x(x^3+8) ?
The derivative of f(x)=3x^2e^x+e^x(x^3+8) is e^xx^3+6e^xx^2+6e^xx+8e^x
What is the first derivative of f(x)=3x^2e^x+e^x(x^3+8) ?
The first derivative of f(x)=3x^2e^x+e^x(x^3+8) is e^xx^3+6e^xx^2+6e^xx+8e^x