What is the solution for (dy)/(dx)=(2x+1)(y+1),y(-1)=1 ?

The solution for (dy)/(dx)=(2x+1)(y+1),y(-1)=1 is y=2e^{x^2+x}-1

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(dy)/(dx)=(2x+1)(y+1),y(-1)=1

\frac{d y}{d x} = (2 x + 1) (y + 1), y (- 1) = 1

y = 2 e^{x^{2} + x} - 1

Solution steps

\frac{d y}{d x} = (2 x + 1) (y + 1)

Solve separable ODE:

y = 2 e^{x^{2} + x} - 1

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x \to 0 + lim (x^{\frac{2}{x}})

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What is the solution for (dy)/(dx)=(2x+1)(y+1),y(-1)=1 ?
The solution for (dy)/(dx)=(2x+1)(y+1),y(-1)=1 is y=2e^{x^2+x}-1