What is the integral from 0 to infinity of 5sin^2(x) ?

The integral from 0 to infinity of 5sin^2(x) is diverges

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integral from 0 to infinity of 5sin^2(x)

\int_{0}^{\infty} 5 sin^{2} (x) d x

diverges

Solution steps

\int_{0}^{\infty} 5 sin^{2} (x) d x

Compute the indefinite integral:

\int 5 sin^{2} (x) d x = \frac{5}{2} (x - \frac{1}{2} sin (2 x)) + C

Compute the boundaries:

\int_{0}^{\infty} 5 sin^{2} (x) d x =

diverges

= diverges

\int_{1}^{6} \frac{x ^{2} + 6}{7 x - x ^{2}} d x

\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

n = 0 \sum \infty \frac{1}{n - 1}

f (x) = (e^{- x} - e^{5}) (e^{x} + e^{- 3})

n = j \sum \infty (\frac{3}{4})^{n}

What is the integral from 0 to infinity of 5sin^2(x) ?
The integral from 0 to infinity of 5sin^2(x) is diverges