What is the d/(dt)(6/5-6/5 e^{-20t}) ?

The d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}

What is the first d/(dt)(6/5-6/5 e^{-20t}) ?

The first d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}

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\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

24 e^{- 20 t}

Solution steps

\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{6}{5}) - \frac{d}{d t} (\frac{6}{5} e^{- 20 t})

\frac{d}{d t} (\frac{6}{5}) = 0

\frac{d}{d t} (\frac{6}{5} e^{- 20 t}) = - 24 e^{- 20 t}

= 0 - (- 24 e^{- 20 t})

Simplify

= 24 e^{- 20 t}

n = 0 \sum \infty \frac{1}{n - 1}

f (x) = (e^{- x} - e^{5}) (e^{x} + e^{- 3})

n = j \sum \infty (\frac{3}{4})^{n}

\frac{1}{( s ^{2} + 16 )}

\int_{1}^{2} e^{- x^{2}} d x

What is the d/(dt)(6/5-6/5 e^{-20t}) ?
The d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}
What is the first d/(dt)(6/5-6/5 e^{-20t}) ?
The first d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}