What is the derivative of \sqrt[4]{17-x} ?

The derivative of \sqrt[4]{17-x} is -1/(4(17-x)^{3/4)}

What is the first derivative of \sqrt[4]{17-x} ?

The first derivative of \sqrt[4]{17-x} is -1/(4(17-x)^{3/4)}

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derivative of

- \frac{1}{4 ( 17 - x ) ^{\frac{3}{4}}}

Solution steps

Apply the chain rule:

\frac{1}{4 ( 17 - x ) ^{\frac{3}{4}}} \frac{d}{d x} (17 - x)

= \frac{1}{4 ( 17 - x ) ^{\frac{3}{4}}} \frac{d}{d x} (17 - x)

\frac{d}{d x} (17 - x) = - 1

= \frac{1}{4 ( 17 - x ) ^{\frac{3}{4}}} (- 1)

Simplify

= - \frac{1}{4 ( 17 - x ) ^{\frac{3}{4}}}

n = 0 \sum \infty \frac{7}{4 ^{n}}

y = (6 x + 5) (x^{2} - 3 x)

\int 8 x cos (4) x^{2} d x

\frac{d}{d y} (e^{x - y})

What is the derivative of \sqrt[4]{17-x} ?
The derivative of \sqrt[4]{17-x} is -1/(4(17-x)^{3/4)}
What is the first derivative of \sqrt[4]{17-x} ?
The first derivative of \sqrt[4]{17-x} is -1/(4(17-x)^{3/4)}