What is the derivative of y=(6x+5)(x^2-3x) ?

The derivative of y=(6x+5)(x^2-3x) is 18x^2-26x-15

What is the first derivative of y=(6x+5)(x^2-3x) ?

The first derivative of y=(6x+5)(x^2-3x) is 18x^2-26x-15

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derivative of

y = (6 x + 5) (x^{2} - 3 x)

18 x^{2} - 26 x - 15

Solution steps

\frac{d}{d x} ((6 x + 5) (x^{2} - 3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6 x + 5, g = x^{2} - 3 x

= \frac{d}{d x} (6 x + 5) (x^{2} - 3 x) + \frac{d}{d x} (x^{2} - 3 x) (6 x + 5)

\frac{d}{d x} (6 x + 5) = 6

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= 6 (x^{2} - 3 x) + (2 x - 3) (6 x + 5)

Simplify

6 (x^{2} - 3 x) + (2 x - 3) (6 x + 5) : 18 x^{2} - 26 x - 15

= 18 x^{2} - 26 x - 15

\int 8 x cos (4) x^{2} d x

\frac{d}{d y} (e^{x - y})

\frac{\partial}{\partial x} (cos (3 x + 6 y))

\frac{d y}{d x} + 0.8 x y = 4 x

What is the derivative of y=(6x+5)(x^2-3x) ?
The derivative of y=(6x+5)(x^2-3x) is 18x^2-26x-15
What is the first derivative of y=(6x+5)(x^2-3x) ?
The first derivative of y=(6x+5)(x^2-3x) is 18x^2-26x-15