What is the integral from 1 to 8 of x/(2\sqrt[3]{x)} ?

The integral from 1 to 8 of x/(2\sqrt[3]{x)} is 93/10

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integral from 1 to 8 of x/(2\sqrt[3]{x)}

\frac{93}{10}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Simplify

= \frac{1}{2} \cdot \int_{1}^{8} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{1}^{8}

= \frac{1}{2} [\frac{3}{5} x^{\frac{5}{3}}]_{1}^{8}

Compute the boundaries:

\frac{93}{5}

= \frac{1}{2} \cdot \frac{93}{5}

Simplify

= \frac{93}{10}

\frac{\partial}{\partial x} (cos (3 x + 6 y))

\frac{d y}{d x} + 0.8 x y = 4 x

\frac{\partial}{\partial x} (x \cdot i)

y \cdot \frac{d y}{d x} = 5 x (9 + y^{2})

x^{2} e^{x^{2}}

What is the integral from 1 to 8 of x/(2\sqrt[3]{x)} ?
The integral from 1 to 8 of x/(2\sqrt[3]{x)} is 93/10