What is the tangent of f(x)=4+4x^2-2x^3,\at x=a ?

The tangent of f(x)=4+4x^2-2x^3,\at x=a is y=(-6a^2+8a)x+4a^3-4a^2+4

Popular >

tangent of f(x)=4+4x^2-2x^3,\at x=a

tangent of

f (x) = 4 + 4 x^{2} - 2 x^{3}, at x = a

y = (- 6 a^{2} + 8 a) x + 4 a^{3} - 4 a^{2} + 4

Solution steps

Find the tangent point:

(a, 4 + 4 a^{2} - 2 a^{3})

Find the slope of

f (x) = 4 + 4 x^{2} - 2 x^{3} : \frac{df ( x )}{d x} = - 6 x^{2} + 8 x

Compute the slope of

f (x) = 4 + 4 x^{2} - 2 x^{3}

x = a : m = - 6 a^{2} + 8 a

Find the line with slope m=

- 6 a^{2} + 8 a

and passing through

(a, 4 + 4 a^{2} - 2 a^{3}) : y = (- 6 a^{2} + 8 a) x + 4 a^{3} - 4 a^{2} + 4

y = (- 6 a^{2} + 8 a) x + 4 a^{3} - 4 a^{2} + 4

t \to 0 lim (sin (6 t))

d y - (2 y - e^{2 x}) d x = 0

\frac{d}{d y} (x^{2} - x y + 2)

\frac{d}{d x} (10 x^{3} tan (x))

x \to 5 lim (x^{2} - 9)

What is the tangent of f(x)=4+4x^2-2x^3,\at x=a ?
The tangent of f(x)=4+4x^2-2x^3,\at x=a is y=(-6a^2+8a)x+4a^3-4a^2+4