What is the integral of-36sin(6x) ?

The integral of-36sin(6x) is 6cos(6x)+C

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integral of-36sin(6x)

\int - 36 sin (6 x) d x

6 cos (6 x) + C

Solution steps

\int - 36 sin (6 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 36 \cdot \int sin (6 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{6} d u

= - 36 \cdot \int sin (u) \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 36 \cdot \frac{1}{6} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - 36 \cdot \frac{1}{6} (- cos (u))

Substitute back

u = 6 x

= - 36 \cdot \frac{1}{6} (- cos (6 x))

Simplify

- 36 \cdot \frac{1}{6} (- cos (6 x)) : 6 cos (6 x)

= 6 cos (6 x)

Add a constant to the solution

= 6 cos (6 x) + C

n = 1 \sum \infty \frac{n !}{2 0 ^{n}}

\int (2 t - 1) d t

\int (2 - x^{2}) d x

y y^{^{'}} - e^{x} = 0

y = 3 - x^{3} (0.3)