What is the tangent of f(x)= 7/x ,\at x=6 ?

The tangent of f(x)= 7/x ,\at x=6 is y=-7/36 x+7/3

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tangent of f(x)= 7/x ,\at x=6

tangent of

f (x) = \frac{7}{x}, at x = 6

y = - \frac{7}{36} x + \frac{7}{3}

Solution steps

Find the tangent point:

(6, \frac{7}{6})

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7}{36}

Find the line with slope m=

- \frac{7}{36}

and passing through

(6, \frac{7}{6}) : y = - \frac{7}{36} x + \frac{7}{3}

y = - \frac{7}{36} x + \frac{7}{3}

y^{^{'}} = \frac{e ^{x} - e ^{y}}{1 + e ^{x}}

\int \frac{sin ( 2 x )}{12 + cos ^{2} ( x )} d x

\frac{2}{( s ^{3} - 7 s ^{2} + 2 s + 40 )}

arccos (∣ x + 1 ∣)

f (x) = 2 x^{2} - 5 x + 3, at a = 2

What is the tangent of f(x)= 7/x ,\at x=6 ?
The tangent of f(x)= 7/x ,\at x=6 is y=-7/36 x+7/3