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Popular >

y^'=-y^{3/2}

Solution

y^{^{'}} = - y^{\frac{3}{2}}

Solution

y = \frac{4}{t ^{2} - 2 c _{1} t + c _{1}^{2}}

Solution steps

y^{'} (t) = - y^{\frac{3}{2}}

Solve separable ODE:

y = \frac{4}{t ^{2} - 2 c _{1} t + c _{1}^{2}}

y = \frac{4}{t ^{2} - 2 c _{1} t + c _{1}^{2}}

Popular Examples

integral of (x^5+1)/(x^6-x^4)

\int \frac{x ^{5} + 1}{x ^{6} - x ^{4}} d x

e^{- x} y^{^{'}} = \frac{x}{y}

x(x+3)dy-y(2x+3)dx=0

x (x + 3) d y - y (2 x + 3) d x = 0

(x^{3} + 2)^{^{'}}

integral of sqrt(2t)-cos(6t)

\int 2 t - cos (6 t) d t

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y^{3/2} ?
The solution for y^'=-y^{3/2} is y= 4/(t^2-2c_{1)t+c_{1}^2}