What is the solution for e^{-x}y^'= x/y ?

The solution for e^{-x}y^'= x/y is y=sqrt(2e^xx-2e^x+c_{1)},y=-sqrt(2e^xx-2e^x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^{-x}y^'= x/y

e^{- x} y^{^{'}} = \frac{x}{y}

y = 2 e^{x} x - 2 e^{x} + c_{1}, y = - 2 e^{x} x - 2 e^{x} + c_{1}

Solution steps

e^{- x} y^{'} (x) = \frac{x}{y}

Solve separable ODE:

y = 2 e^{x} x - 2 e^{x} + c_{1}, y = - 2 e^{x} x - 2 e^{x} + c_{1}

y = 2 e^{x} x - 2 e^{x} + c_{1}, y = - 2 e^{x} x - 2 e^{x} + c_{1}

x (x + 3) d y - y (2 x + 3) d x = 0

(x^{3} + 2)^{^{'}}

\int 2 t - cos (6 t) d t

\int_{0}^{1} \frac{34}{4 y - 1} d y

y^{^{'}} = e^{2 x - 1} y^{2}

What is the solution for e^{-x}y^'= x/y ?
The solution for e^{-x}y^'= x/y is y=sqrt(2e^xx-2e^x+c_{1)},y=-sqrt(2e^xx-2e^x+c_{1)}