What is area y=-x^2+2x+2,y=x-4 ?

The answer to area y=-x^2+2x+2,y=x-4 is 125/6

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area y=-x^2+2x+2,y=x-4

area

y = - x^{2} + 2 x + 2, y = x - 4

\frac{125}{6}

Decimal Notation

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} - x^{2} + 2 x + 2 - (x - 4) d x

Solve

\int_{- 2}^{3} - x^{2} + 2 x + 2 - (x - 4) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

\int \frac{d ^{2} y}{1} d x^{2}

\int (sin^{2} (x) + cos^{2} (x) - 1) d x

\int - \frac{6 x}{5} d x

y = (x^{3} - 25 x)^{14}

f (x) = (8 - x)^{6}