What is the integral of (6e^x)/(sqrt(1-e^{2x))} ?

The integral of (6e^x)/(sqrt(1-e^{2x))} is 6arcsin(e^x)+C

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integral of (6e^x)/(sqrt(1-e^{2x))}

\int \frac{6 e ^{x}}{1 - e ^{2 x}} d x

6 arcsin (e^{x}) + C

Solution steps

\int \frac{6 e ^{x}}{1 - e ^{2 x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{e ^{x}}{1 - e ^{2 x}} d x

Apply u-substitution

: \int \frac{1}{1 - u ^{2}} d u

= 6 \cdot \int \frac{1}{1 - u ^{2}} d u

Use the common integral:

\int \frac{1}{1 - u ^{2}} d u = arcsin (u)

= 6 arcsin (u)

Substitute back

u = e^{x}

= 6 arcsin (e^{x})

Add a constant to the solution

= 6 arcsin (e^{x}) + C

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What is the integral of (6e^x)/(sqrt(1-e^{2x))} ?
The integral of (6e^x)/(sqrt(1-e^{2x))} is 6arcsin(e^x)+C