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Popular >

area-x^2+y=1,[2,-2]

Solution

area

- x^{2} + y = 1, [2, - 2]

Solution

\frac{28}{3}

+1

Decimal Notation

9.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 1 + x^{2} d x

Solve

\int_{- 2}^{2} 1 + x^{2} d x : \frac{28}{3}

The area is:

= \frac{28}{3}

Popular Examples

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x \to 1 + lim (\frac{x ^{2} - 8 x + 15}{x - 1})

2xydx+(x^2+1)dy=3xdx

2 x y d x + (x^{2} + 1) d y = 3 x d x

(\partial)/(\partial r)(e^rcos(θ))

\frac{\partial}{\partial r} (e^{r} cos (θ))

integral of (x^2-2x+1)/(sqrt(x^2-2x+10))

\int \frac{x ^{2} - 2 x + 1}{x ^{2} - 2 x + 10} d x

Frequently Asked Questions (FAQ)

What is area-x^2+y=1,[2,-2] ?
The answer to area-x^2+y=1,[2,-2] is 28/3