What is the limit as x approaches 1+of (x^2-8x+15)/(x-1) ?

The limit as x approaches 1+of (x^2-8x+15)/(x-1) is infinity

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limit as x approaches 1+of (x^2-8x+15)/(x-1)

x \to 1 + lim (\frac{x ^{2} - 8 x + 15}{x - 1})

\infty

Solution steps

x \to 1 + lim (\frac{x ^{2} - 8 x + 15}{x - 1})

\frac{x ^{2} - 8 x + 15}{x - 1} = (x^{2} - 8 x + 15) \frac{1}{x - 1}

= x \to 1 + lim ((x^{2} - 8 x + 15) \frac{1}{x - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 + lim (x^{2} - 8 x + 15) \cdot x \to 1 + lim (\frac{1}{x - 1})

x \to 1 + lim (x^{2} - 8 x + 15) = 8

x \to 1 + lim (\frac{1}{x - 1}) = \infty

= 8 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

2 x y d x + (x^{2} + 1) d y = 3 x d x

\frac{\partial}{\partial r} (e^{r} cos (θ))

\int \frac{x ^{2} - 2 x + 1}{x ^{2} - 2 x + 10} d x

\int (2 x^{2} + 5) (x^{2} - 3 x) d x

\int \frac{1}{y ^{3}} d y

What is the limit as x approaches 1+of (x^2-8x+15)/(x-1) ?
The limit as x approaches 1+of (x^2-8x+15)/(x-1) is infinity