What is inverse oflaplace g(s)= 5/(s-3) ?

The answer to inverse oflaplace g(s)= 5/(s-3) is 5e^{3t}

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inverse oflaplace g(s)= 5/(s-3)

inverse laplace

g (s) = \frac{5}{s - 3}

5 e^{3 t}

Solution steps

L^{- 1} {\frac{5}{s - 3}}

= L^{- 1} {5 \cdot \frac{1}{s - 3}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 5 L^{- 1} {\frac{1}{s - 3}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 3}} = e^{3 t}

= 5 e^{3 t}

\frac{d}{d x} (- 2 x cos (x))

\frac{5}{2} y^{4} y^{^{'}} = \frac{y ^{5} + 4}{x ^{3}}

(2 x + y) d x + (x + 3 y) d y = 0

y = 4 x^{2} - x^{3}, (1, 3)

e^{x}, e^{2 x}, ln (2), ln (4)

What is inverse oflaplace g(s)= 5/(s-3) ?
The answer to inverse oflaplace g(s)= 5/(s-3) is 5e^{3t}