en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of-2xcos(x)

Solution

\frac{d}{d x} (- 2 x cos (x))

Solution

- 2 (cos (x) - x sin (x))

Solution steps

\frac{d}{d x} (- 2 x cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (x)

= - 2 (\frac{d x}{d x} cos (x) + \frac{d}{d x} (cos (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (cos (x)) = - sin (x)

= - 2 (1 \cdot cos (x) + (- sin (x)) x)

Simplify

= - 2 (cos (x) - x sin (x))

Popular Examples

5/2 y^4y^'=(sqrt(y^5+4))/(x^3)

\frac{5}{2} y^{4} y^{^{'}} = \frac{y ^{5} + 4}{x ^{3}}

(2x+y)dx+(x+3y)dy=0

(2 x + y) d x + (x + 3 y) d y = 0

tangent of y=4x^2-x^3,(1,3)tangent of

y = 4 x^{2} - x^{3}, (1, 3)

area e^x,e^{2x},ln(2),ln(4)area

e^{x}, e^{2 x}, ln (2), ln (4)

(\partial)/(\partial x)(sqrt(8-3x^2-y^2))

\frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2})

Frequently Asked Questions (FAQ)

What is the derivative of-2xcos(x) ?
The derivative of-2xcos(x) is -2(cos(x)-xsin(x))
What is the first derivative of-2xcos(x) ?
The first derivative of-2xcos(x) is -2(cos(x)-xsin(x))