What is the tangent of y= 1/(x^5),(-2,-1/32) ?

The tangent of y= 1/(x^5),(-2,-1/32) is y=-5/64 x-3/16

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tangent of y= 1/(x^5),(-2,-1/32)

tangent of

y = \frac{1}{x ^{5}}, (- 2, - \frac{1}{32})

y = - \frac{5}{64} x - \frac{3}{16}

Solution steps

Find the slope of

y = \frac{1}{x ^{5}} : \frac{d y}{d x} = - \frac{5}{x ^{6}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{5}{64}

Find the line with slope m=

- \frac{5}{64}

and passing through

(- 2, - \frac{1}{32}) : y = - \frac{5}{64} x - \frac{3}{16}

y = - \frac{5}{64} x - \frac{3}{16}

\int \frac{2}{( x - 4 ) ( x ^{2} + 2 x + 6 )} d x

y = e^{4 x^{2} + 1}

\frac{5 t}{1 + 2 t ^{2}}

f (x) = 7 x + 1, (9, 8)

\int \frac{a}{a ^{2} + x ^{2}} d x

What is the tangent of y= 1/(x^5),(-2,-1/32) ?
The tangent of y= 1/(x^5),(-2,-1/32) is y=-5/64 x-3/16