What is the limit as t approaches 0 of 2e^{-t} ?

The limit as t approaches 0 of 2e^{-t} is 2

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limit as t approaches 0 of 2e^{-t}

t \to 0 lim (2 e^{- t})

2

Solution steps

t \to 0 lim (2 e^{- t})

Plug in the value

t = 0

= 2 e^{- 0}

Simplify

= 2

x \to 0 lim (\frac{8 x ^{2} - 2 x}{2 x})

\int (2 x - x)^{2} d x

\frac{\partial}{\partial x} (4 sin (x) cos (y))

\frac{\partial}{\partial K} (L^{\frac{1}{2}} K^{\frac{1}{2}})

x \to 4 lim (x + 4)

What is the limit as t approaches 0 of 2e^{-t} ?
The limit as t approaches 0 of 2e^{-t} is 2