What is (\partial)/(\partial s)(-3s^2t^2) ?

The answer to (\partial)/(\partial s)(-3s^2t^2) is -6st^2

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(\partial)/(\partial s)(-3s^2t^2)

\frac{\partial}{\partial s} (- 3 s^{2} t^{2})

- 6 s t^{2}

Solution steps

\frac{\partial}{\partial s} (- 3 s^{2} t^{2})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 t^{2} \frac{\partial}{\partial s} (s^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 t^{2} \cdot 2 s^{2 - 1}

Simplify

= - 6 s t^{2}

\frac{d y}{d x} = \frac{y ^{3}}{3 x + 1}, y (0) = - 1

\frac{2}{t ^{3}}

y^{^{'}} + 3 y = x e^{- 2 x}

\frac{\partial}{\partial y} (- sin (x) sin (y))

n = 0 \sum \infty \frac{( x ^{n} )}{n}

What is (\partial)/(\partial s)(-3s^2t^2) ?
The answer to (\partial)/(\partial s)(-3s^2t^2) is -6st^2