What is the solution for y^{''}+3y^'=0,y(0)=2 ?

The solution for y^{''}+3y^'=0,y(0)=2 is y=2-c_{2}+c_{2}e^{-3t}

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y^{''}+3y^'=0,y(0)=2

y^{^{''}} + 3 y^{^{'}} = 0, y (0) = 2

y = 2 - c_{2} + c_{2} e^{- 3 t}

Solution steps

y^{''} (t) + 3 y^{'} (t) = 0

Solve linear ODE:

y = 2 - c_{2} + c_{2} e^{- 3 t}

y = 2 - c_{2} + c_{2} e^{- 3 t}

\int cos^{2} (x s i) n^{2} x d x

\frac{d x}{d y} = \frac{( x ^{2} y ^{2} )}{1 + x}

x \to 0 lim ((x)^{s i n (x)})

\frac{1960}{s ^{2} + 196}

y^{^{'}} = - 3 y + 2 e^{- x}

What is the solution for y^{''}+3y^'=0,y(0)=2 ?
The solution for y^{''}+3y^'=0,y(0)=2 is y=2-c_{2}+c_{2}e^{-3t}