What is the solution for (dx)/(dy)=((x^2y^2))/(1+x) ?

The solution for (dx)/(dy)=((x^2y^2))/(1+x) is x= 1/(\W((1){e^{\frac{y^3+c_{1})/3}})}

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(dx)/(dy)=((x^2y^2))/(1+x)

\frac{d x}{d y} = \frac{( x ^{2} y ^{2} )}{1 + x}

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

Solution steps

\frac{d x}{d y} = \frac{( x ^{2} y ^{2} )}{1 + x}

Solve separable ODE:

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

x \to 0 lim ((x)^{s i n (x)})

\frac{1960}{s ^{2} + 196}

y^{^{'}} = - 3 y + 2 e^{- x}

(4, - 2), (- 8, - 1)

x \to 3 lim (25 - x^{2})

What is the solution for (dx)/(dy)=((x^2y^2))/(1+x) ?
The solution for (dx)/(dy)=((x^2y^2))/(1+x) is x= 1/(\W((1){e^{\frac{y^3+c_{1})/3}})}