What is the limit as x approaches 1 of ln(2x)+e^x ?

The limit as x approaches 1 of ln(2x)+e^x is ln(2)+e

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limit as x approaches 1 of ln(2x)+e^x

x \to 1 lim (ln (2 x) + e^{x})

ln (2) + e

Solution steps

x \to 1 lim (ln (2 x) + e^{x})

Plug in the value

x = 1

= ln (2 \cdot 1) + e^{1}

Simplify

= ln (2) + e

\frac{11}{( s - 1 ) ^{3}}

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n = 0 \sum \infty 2 x^{2 n}

\int_{3}^{\infty} e^{- x} d x

x \to 3 + lim (\frac{3}{x ^{2} - 9})

What is the limit as x approaches 1 of ln(2x)+e^x ?
The limit as x approaches 1 of ln(2x)+e^x is ln(2)+e