What is the sum from n=2 to infinity of n/(3n^3+1) ?

The sum from n=2 to infinity of n/(3n^3+1) is converges

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sum from n=2 to infinity of n/(3n^3+1)

n = 2 \sum \infty \frac{n}{3 n ^{3} + 1}

converges

Solution steps

n = 2 \sum \infty \frac{n}{3 n ^{3} + 1}

Apply Series Comparison Test:

converges

= converges

\frac{8}{1 - x}

\frac{d}{d t} (4 t^{2} + 2 t + 5)

\frac{d}{d x} (e^{c o s (x)} + e^{s i n (y)})

\frac{d}{d x} (lo g_{3} (5 x - 1))

y = \frac{5}{x}, (4, \frac{5}{4})

What is the sum from n=2 to infinity of n/(3n^3+1) ?
The sum from n=2 to infinity of n/(3n^3+1) is converges