What is the solution for (2x^3+xy^2)+(x^2y+2y^3)(dy)/(dx)=0 ?

The solution for (2x^3+xy^2)+(x^2y+2y^3)(dy)/(dx)=0 is

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(2x^3+xy^2)+(x^2y+2y^3)(dy)/(dx)=0

(2 x^{3} + x y^{2}) + (x^{2} y + 2 y^{3}) \frac{d y}{d x} = 0

y = \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}

Solution steps

(2 x^{3} + x y^{2}) + (x^{2} y + 2 y^{3}) \frac{d y}{d x} = 0

Solve exact ODE:

y = \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}

y = \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} + - 3 x ^{4} + c _{1}}{2}, y = \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}, y = - \frac{- x ^{2} - - 3 x ^{4} + c _{1}}{2}

\int_{0}^{t} e^{- s^{2}} d s

x \to - 5 lim (\frac{x ^{2} - 2}{5 - x})

\int \frac{x ^{3}}{3} \cdot \frac{1}{x} d x

\int \frac{- ln ( x )}{x ^{2}} d x

3 + y^{2}

What is the solution for (2x^3+xy^2)+(x^2y+2y^3)(dy)/(dx)=0 ?
The solution for (2x^3+xy^2)+(x^2y+2y^3)(dy)/(dx)=0 is