What is (\partial)/(\partial x)(e^{x^2-y}) ?

The answer to (\partial)/(\partial x)(e^{x^2-y}) is e^{x^2-y}*2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^{x^2-y})

\frac{\partial}{\partial x} (e^{x^{2} - y})

e^{x^{2} - y} \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (e^{x^{2} - y})

Treat

y

as a constant

Apply the chain rule:

e^{x^{2} - y} \frac{\partial}{\partial x} (x^{2} - y)

= e^{x^{2} - y} \frac{\partial}{\partial x} (x^{2} - y)

\frac{\partial}{\partial x} (x^{2} - y) = 2 x

= e^{x^{2} - y} \cdot 2 x

8 x + 9 x e^{x}

\int 2 ln (t) d t

y^{^{'}} = 1 - 7 x^{2}

\int \frac{x - 2}{x + 3} d x

\int cos (\frac{nπ x}{L}) d x

What is (\partial)/(\partial x)(e^{x^2-y}) ?
The answer to (\partial)/(\partial x)(e^{x^2-y}) is e^{x^2-y}*2x