What is (\partial)/(\partial x)(3y-x/(y^2)) ?

The answer to (\partial)/(\partial x)(3y-x/(y^2)) is -1/(y^2)

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(\partial)/(\partial x)(3y-x/(y^2))

\frac{\partial}{\partial x} (3 y - \frac{x}{y ^{2}})

- \frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (3 y - \frac{x}{y ^{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y) - \frac{\partial}{\partial x} (\frac{x}{y ^{2}})

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (\frac{x}{y ^{2}}) = \frac{1}{y ^{2}}

= 0 - \frac{1}{y ^{2}}

Simplify

= - \frac{1}{y ^{2}}

2 - 0.5 e^{- 10 t}

f (x) = \frac{x ^{2} - 1}{x - 1}

x \to - 5 lim (\frac{4 ( 2 x + 3 ) ^{2} - 196}{x + 5})

\frac{d}{d x} (ln (\frac{( 2 x + 1 ) ^{2}}{( x - 1 )}))

What is (\partial)/(\partial x)(3y-x/(y^2)) ?
The answer to (\partial)/(\partial x)(3y-x/(y^2)) is -1/(y^2)