en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+9xe^y=0

Solution

y^{^{'}} + 9 x e^{y} = 0

Solution

y = - ln (\frac{9 x ^{2}}{2} - c_{1})

Solution steps

y^{'} (x) + 9 x e^{y} = 0

Solve separable ODE:

y = - ln (\frac{9 x ^{2}}{2} - c_{1})

y = - ln (\frac{9 x ^{2}}{2} - c_{1})

Popular Examples

integral of (x-1)^2(e^{x+1}-1)

\int (x - 1)^{2} (e^{x + 1} - 1) d x

tangent of x^2-7x+7 tangent of

x^{2} - 7 x + 7

(\partial}{\partial y}(\frac{3x)/y)

\frac{\partial}{\partial y} (\frac{3 x}{y})

derivative of 2-cos(x)

\frac{d}{d x} (2 - cos (x))

(\partial)/(\partial x)(xy+6x)

\frac{\partial}{\partial x} (x y + 6 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+9xe^y=0 ?
The solution for y^'+9xe^y=0 is y=-ln((9x^2)/2-c_{1})