What is the tangent of y=x+sqrt(x),(9,12) ?

The tangent of y=x+sqrt(x),(9,12) is y= 7/6 x+3/2

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tangent of y=x+sqrt(x),(9,12)

tangent of

y = x + x, (9, 12)

y = \frac{7}{6} x + \frac{3}{2}

Solution steps

Find the slope of

y = x + x : \frac{d y}{d x} = 1 + \frac{1}{2 x}

Compute the slope of

y = x + x

(9, 12) : m = \frac{7}{6}

Find the line with slope m=

\frac{7}{6}

and passing through

(9, 12) : y = \frac{7}{6} x + \frac{3}{2}

y = \frac{7}{6} x + \frac{3}{2}

\frac{d}{d x} (\frac{x ^{3}}{12} + \frac{2}{3} x^{- 3})

\frac{d}{d x} (- 8 e^{- \frac{x}{10}} - 40)

\int_{0}^{8} \frac{4}{( x - 6 ) ^{3}} d x

f (x) = (1 + 2 x)^{10}, (0, 1)

\frac{\partial}{\partial x} (\frac{3 x y ^{2}}{x ^{2} + y ^{4}})

What is the tangent of y=x+sqrt(x),(9,12) ?
The tangent of y=x+sqrt(x),(9,12) is y= 7/6 x+3/2