What is the integral from 0 to 8 of 4/((x-6)^3) ?

The integral from 0 to 8 of 4/((x-6)^3) is diverges

Popular >

integral from 0 to 8 of 4/((x-6)^3)

\int_{0}^{8} \frac{4}{( x - 6 ) ^{3}} d x

diverges

Solution steps

\int_{0}^{8} \frac{4}{( x - 6 ) ^{3}} d x

Find undefined (singularity) points:

x = 6

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{6} \frac{4}{( x - 6 ) ^{3}} d x + \int_{6}^{8} \frac{4}{( x - 6 ) ^{3}} d x

\int_{0}^{6} \frac{4}{( x - 6 ) ^{3}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

f (x) = (1 + 2 x)^{10}, (0, 1)

\frac{\partial}{\partial x} (\frac{3 x y ^{2}}{x ^{2} + y ^{4}})

\int 5 x e^{4 x} d x

\int (3 x - 4) \cdot e^{- x} d x

\int sin (\frac{( nπ x )}{2}) d x

What is the integral from 0 to 8 of 4/((x-6)^3) ?
The integral from 0 to 8 of 4/((x-6)^3) is diverges