What is the derivative of 2e^x+e^xx ?

The derivative of 2e^x+e^xx is e^xx+3e^x

What is the first derivative of 2e^x+e^xx ?

The first derivative of 2e^x+e^xx is e^xx+3e^x

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\frac{d}{d x} (2 e^{x} + e^{x} x)

e^{x} x + 3 e^{x}

Solution steps

\frac{d}{d x} (2 e^{x} + e^{x} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) + \frac{d}{d x} (e^{x} x)

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d}{d x} (e^{x} x) = e^{x} x + e^{x}

= 2 e^{x} + e^{x} x + e^{x}

Simplify

= e^{x} x + 3 e^{x}

\int 2 x x - \frac{1}{x} d x

\frac{d}{d x} (ln (52 x))

\frac{d y}{d x} + 9 x y = 8 x

\int_{0}^{6} \frac{π}{9} (36 - y^{2}) d y

(sin (x) - x cos (x))^{^{'}}

What is the derivative of 2e^x+e^xx ?
The derivative of 2e^x+e^xx is e^xx+3e^x
What is the first derivative of 2e^x+e^xx ?
The first derivative of 2e^x+e^xx is e^xx+3e^x