What is the tangent of f(x)=4e^xcos(x),\at x=0 ?

The tangent of f(x)=4e^xcos(x),\at x=0 is y=4x+4

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tangent of f(x)=4e^xcos(x),\at x=0

tangent of

f (x) = 4 e^{x} cos (x), at x = 0

y = 4 x + 4

Solution steps

Find the tangent point:

(0, 4)

Find the slope of

f (x) = 4 e^{x} cos (x) : \frac{df ( x )}{d x} = 4 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

f (x) = 4 e^{x} cos (x)

x = 0 : m = 4

Find the line with slope m=

4

and passing through

(0, 4) : y = 4 x + 4

y = 4 x + 4

y = \frac{5 x ^{2} + 4}{x + 3}

\int_{0}^{\frac{π}{4}} x sin (8 x) d x

x^{2} ln (9 + x)

y = 2 x, (32, 8)

\int cos (14 x) cos (5 x) d x

What is the tangent of f(x)=4e^xcos(x),\at x=0 ?
The tangent of f(x)=4e^xcos(x),\at x=0 is y=4x+4