What is inverse oflaplace 1/(3s+5) ?

The answer to inverse oflaplace 1/(3s+5) is 1/3 e^{-(5t)/3}

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inverse oflaplace 1/(3s+5)

inverse laplace

\frac{1}{3 s + 5}

\frac{1}{3} e^{- \frac{5 t}{3}}

Solution steps

L^{- 1} {\frac{1}{3 s + 5}}

= L^{- 1} {\frac{1}{3} \cdot \frac{1}{s + \frac{5}{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{3} L^{- 1} {\frac{1}{s + \frac{5}{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + \frac{5}{3}}} = e^{- \frac{5 t}{3}}

= \frac{1}{3} e^{- \frac{5 t}{3}}

\frac{d}{d x} (\frac{x ^{2} + 3 x}{- 6})

\frac{d y}{d x} - 4 y = \frac{48 x}{y ^{2}}

\frac{\partial}{\partial x} (ln (x^{6} + y^{7}))

\frac{d}{d x} (3 arcsin (x^{4}))

What is inverse oflaplace 1/(3s+5) ?
The answer to inverse oflaplace 1/(3s+5) is 1/3 e^{-(5t)/3}