What is the tangent of f(x)= 1/(x^5),\at x=1 ?

The tangent of f(x)= 1/(x^5),\at x=1 is y=-5x+6

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tangent of f(x)= 1/(x^5),\at x=1

tangent of

f (x) = \frac{1}{x ^{5}}, at x = 1

y = - 5 x + 6

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{x ^{5}} : \frac{df ( x )}{d x} = - \frac{5}{x ^{6}}

Compute the slope of

f (x) = \frac{1}{x ^{5}}

x = 1 : m = - 5

Find the line with slope m=

- 5

and passing through

(1, 1) : y = - 5 x + 6

y = - 5 x + 6

\int \frac{t ^{6}}{1 - t ^{14}} d t

x \to a + lim (g (x))

\int x^{2} + 3 x + 2 d x

t - e^{- 3 t}

\frac{\partial}{\partial x} (\frac{- 3}{y - 3 x})

What is the tangent of f(x)= 1/(x^5),\at x=1 ?
The tangent of f(x)= 1/(x^5),\at x=1 is y=-5x+6