What is the tangent of y=3+sqrt(7-x),(3,5) ?

The tangent of y=3+sqrt(7-x),(3,5) is y=-1/4 x+23/4

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tangent of y=3+sqrt(7-x),(3,5)

tangent of

y = 3 + 7 - x, (3, 5)

y = - \frac{1}{4} x + \frac{23}{4}

Solution steps

Find the slope of

y = 3 + 7 - x : \frac{d y}{d x} = - \frac{1}{2 - x + 7}

Compute the slope of

y = 3 + 7 - x

(3, 5) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(3, 5) : y = - \frac{1}{4} x + \frac{23}{4}

y = - \frac{1}{4} x + \frac{23}{4}

y = 2 x^{2} - 3 x + 1, (3, 10)

\frac{d}{d x} (x + \frac{8}{x})

\frac{d}{d x} (x^{0.4})

e^{2 t} cos (5) (t)

e^{2 x}, e^{6 x}, x = 1

What is the tangent of y=3+sqrt(7-x),(3,5) ?
The tangent of y=3+sqrt(7-x),(3,5) is y=-1/4 x+23/4