What is the derivative of x+8/x ?

The derivative of x+8/x is 1-8/(x^2)

What is the first derivative of x+8/x ?

The first derivative of x+8/x is 1-8/(x^2)

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\frac{d}{d x} (x + \frac{8}{x})

1 - \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{8}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= 1 - \frac{8}{x ^{2}}

\frac{d}{d x} (x^{0.4})

e^{2 t} cos (5) (t)

e^{2 x}, e^{6 x}, x = 1

\frac{d}{d x} (- 2 x - 4)

x \to 1 lim (\frac{cos ( π x )}{3})

What is the derivative of x+8/x ?
The derivative of x+8/x is 1-8/(x^2)
What is the first derivative of x+8/x ?
The first derivative of x+8/x is 1-8/(x^2)