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Popular >

yy^'=x(y-1)

Solution

y y^{^{'}} = x (y - 1)

Solution

y = W (\frac{1}{e ^{\frac{- c _{1} - x ^{2}}{2}}}) + 1

Solution steps

y y^{'} (x) = x (y - 1)

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- c _{1} - x ^{2}}{2}}}) + 1

y = W (\frac{1}{e ^{\frac{- c _{1} - x ^{2}}{2}}}) + 1

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Frequently Asked Questions (FAQ)

What is the solution for yy^'=x(y-1) ?
The solution for yy^'=x(y-1) is y=\W(1/(e^{(-c_{1)-x^2)/2}})+1