What is the derivative of y=(x^2+7x+1)^3 ?

The derivative of y=(x^2+7x+1)^3 is 3(x^2+7x+1)^2(2x+7)

What is the first derivative of y=(x^2+7x+1)^3 ?

The first derivative of y=(x^2+7x+1)^3 is 3(x^2+7x+1)^2(2x+7)

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derivative of

y = (x^{2} + 7 x + 1)^{3}

3 (x^{2} + 7 x + 1)^{2} (2 x + 7)

Solution steps

\frac{d}{d x} ((x^{2} + 7 x + 1)^{3})

Apply the chain rule:

3 (x^{2} + 7 x + 1)^{2} \frac{d}{d x} (x^{2} + 7 x + 1)

= 3 (x^{2} + 7 x + 1)^{2} \frac{d}{d x} (x^{2} + 7 x + 1)

\frac{d}{d x} (x^{2} + 7 x + 1) = 2 x + 7

= 3 (x^{2} + 7 x + 1)^{2} (2 x + 7)

\frac{\partial}{\partial x} (e^{2 z} - x yz)

\int x 1 - x d x

9 y^{^{''}} - 81 y = 0

2 t^{3 π}

\int_{1}^{4} \frac{x - 1}{x} d x

What is the derivative of y=(x^2+7x+1)^3 ?
The derivative of y=(x^2+7x+1)^3 is 3(x^2+7x+1)^2(2x+7)
What is the first derivative of y=(x^2+7x+1)^3 ?
The first derivative of y=(x^2+7x+1)^3 is 3(x^2+7x+1)^2(2x+7)