What is the integral of (sec^2(x)-7) ?

The integral of (sec^2(x)-7) is tan(x)-7x+C

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integral of (sec^2(x)-7)

\int (sec^{2} (x) - 7) d x

tan (x) - 7 x + C

Solution steps

\int sec^{2} (x) - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x - \int 7 d x

\int sec^{2} (x) d x = tan (x)

\int 7 d x = 7 x

= tan (x) - 7 x

Add a constant to the solution

= tan (x) - 7 x + C

f (x) = \frac{3 x}{x - 2}

h \to 0 lim (\frac{( h - 1 ) ^{3} + 1}{h})

f (x) = \frac{1 - 2 x}{3 - x}

\frac{d}{d x} (x + 7)

\int [6 cos (x) - 2 sec (x) tan (x)] d x

What is the integral of (sec^2(x)-7) ?
The integral of (sec^2(x)-7) is tan(x)-7x+C