What is the derivative of f(x)=(3x)/(x-2) ?

The derivative of f(x)=(3x)/(x-2) is -6/((x-2)^2)

What is the first derivative of f(x)=(3x)/(x-2) ?

The first derivative of f(x)=(3x)/(x-2) is -6/((x-2)^2)

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derivative of

f (x) = \frac{3 x}{x - 2}

- \frac{6}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x}{x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} ( x - 2 ) - \frac{d}{d x} ( x - 2 ) x}{( x - 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x - 2) = 1

= 3 \cdot \frac{1 \cdot ( x - 2 ) - 1 \cdot x}{( x - 2 ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot ( x - 2 ) - 1 \cdot x}{( x - 2 ) ^{2}} : - \frac{6}{( x - 2 ) ^{2}}

= - \frac{6}{( x - 2 ) ^{2}}

h \to 0 lim (\frac{( h - 1 ) ^{3} + 1}{h})

f (x) = \frac{1 - 2 x}{3 - x}

\frac{d}{d x} (x + 7)

\int [6 cos (x) - 2 sec (x) tan (x)] d x

\int sec (u) tan (u) d u

What is the derivative of f(x)=(3x)/(x-2) ?
The derivative of f(x)=(3x)/(x-2) is -6/((x-2)^2)
What is the first derivative of f(x)=(3x)/(x-2) ?
The first derivative of f(x)=(3x)/(x-2) is -6/((x-2)^2)