What is (\partial)/(\partial y)(sin(2x+y)) ?

The answer to (\partial)/(\partial y)(sin(2x+y)) is cos(2x+y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(2x+y))

\frac{\partial}{\partial y} (sin (2 x + y))

cos (2 x + y)

Solution steps

\frac{\partial}{\partial y} (sin (2 x + y))

Treat

x

as a constant

Apply the chain rule:

cos (2 x + y) \frac{\partial}{\partial y} (2 x + y)

= cos (2 x + y) \frac{\partial}{\partial y} (2 x + y)

\frac{\partial}{\partial y} (2 x + y) = 1

= cos (2 x + y) \cdot 1

Simplify

= cos (2 x + y)

f (x) = 6 x, at x = 9

\int 2 e^{x} x d x

\int \frac{( 6 x - 9 )}{( x ^{2} - 3 x + 5 ) ^{3}} d x

\frac{d}{d x} (- \frac{1}{3} cos (3 x))

y = ln (x^{5})

What is (\partial)/(\partial y)(sin(2x+y)) ?
The answer to (\partial)/(\partial y)(sin(2x+y)) is cos(2x+y)