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Popular >

integral from-1 to 1 of x^2-1

Solution

\int_{- 1}^{1} x^{2} - 1 d x

Solution

- \frac{4}{3}

+1

Solution steps

\int_{- 1}^{1} x^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x - \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 1 d x = 2

= \frac{2}{3} - 2

Simplify

\frac{2}{3} - 2 : - \frac{4}{3}

= - \frac{4}{3}

Popular Examples

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\int_{0}^{0.5} 750 x d x

tangent of 2e^xcos(x)tangent of

2 e^{x} cos (x)

y^'+(1/x-1)y=-2/x

y^{^{'}} + (\frac{1}{x} - 1) y = - \frac{2}{x}

derivative of 5(2-x^3^4)

\frac{d}{d x} (5 (2 - x^{3})^{4})

(\partial)/(\partial x)(-3y^5sin(3x))

\frac{\partial}{\partial x} (- 3 y^{5} sin (3 x))

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x^2-1 ?
The integral from-1 to 1 of x^2-1 is -4/3