What is the derivative of f(x)=(11)/(ln(x)) ?

The derivative of f(x)=(11)/(ln(x)) is -(11)/(xln^2(x))

What is the first derivative of f(x)=(11)/(ln(x)) ?

The first derivative of f(x)=(11)/(ln(x)) is -(11)/(xln^2(x))

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derivative of

f (x) = \frac{11}{ln ( x )}

- \frac{11}{x ln ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{11}{ln ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 11 \frac{d}{d x} (\frac{1}{ln ( x )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 11 \frac{d}{d x} (ln^{- 1} (x))

Apply the chain rule:

- \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

= - \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 11 (- \frac{1}{( ln ( x ) ) ^{2}} \cdot \frac{1}{x})

Simplify

11 (- \frac{1}{ln ^{2} ( x )} \cdot \frac{1}{x}) : - \frac{11}{x ln ^{2} ( x )}

= - \frac{11}{x ln ^{2} ( x )}

\int \frac{( 2 x ^{2} - 3 )}{( x - 2 ) ( x ^{2} + 4 )} d x

\frac{d}{d x} ((6 x + 7) (7 x - 8))

\int x^{2} x^{e} d x

\int 3^{5 x - 1} d x

\frac{3 d y}{d x} = y^{2}

What is the derivative of f(x)=(11)/(ln(x)) ?
The derivative of f(x)=(11)/(ln(x)) is -(11)/(xln^2(x))
What is the first derivative of f(x)=(11)/(ln(x)) ?
The first derivative of f(x)=(11)/(ln(x)) is -(11)/(xln^2(x))