What is the derivative of e^{-0.5x} ?

The derivative of e^{-0.5x} is -0.5e^{-0.5x}

What is the first derivative of e^{-0.5x} ?

The first derivative of e^{-0.5x} is -0.5e^{-0.5x}

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derivative of

e^{- 0.5 x}

- 0.5 e^{- 0.5 x}

Solution steps

\frac{d}{d x} (e^{- 0.5 x})

Apply the chain rule:

e^{- 0.5 x} \frac{d}{d x} (- 0.5 x)

= e^{- 0.5 x} \frac{d}{d x} (- 0.5 x)

\frac{d}{d x} (- 0.5 x) = - 0.5

= e^{- 0.5 x} (- 0.5)

Simplify

= - 0.5 e^{- 0.5 x}

\frac{d}{d t} ((A t^{2} + Bt + C) (sin (2 t) + cos (2 t)))

x \to \infty lim (\frac{x}{r})

f (x) = \frac{x ^{2} - 1}{x + 1}

\frac{d}{d x} (\frac{2}{5} x^{5} - 4 x^{3} + 9 x^{2} - 6 x - 2)

x \to 1 + lim (ln (x^{5} - 1))

What is the derivative of e^{-0.5x} ?
The derivative of e^{-0.5x} is -0.5e^{-0.5x}
What is the first derivative of e^{-0.5x} ?
The first derivative of e^{-0.5x} is -0.5e^{-0.5x}